题解 | #矩阵转置#

#include <stdio.h>

int main() {

    int n = 0;//行
    int m = 0;//列
    scanf("%d %d", &n, &m);//输入
    int arr1[n][m];
    int i = 0;

    for (i = 0; i < n; i++)//遍历输入
    {
        int j = 0;
        for (j = 0; j < m; j++)
        {
            scanf("%d ", &arr1[i][j]);
        }
    }
    int arr2[m][n];

    for (i = 0; i < n; i++)//转置
    {
        int j = 0;
        for (j = 0; j < m; j++)
        {
            arr2[j][i]=arr1[i][j];
        }
    }

    for (i = 0; i < m; i++)//打印输出
    {
        int j = 0;
        for (j = 0; j < n; j++)
        {
            printf("%d ", arr2[i][j]);
        }
        printf("\n");
    }
    return 0;
}