题解 | #字符串分隔#

字符串分割 Java解法 11ms

使用BufferedReader按行读取字符串；
int patchLen = 8 - s.length() % 8; 计算需要补足的位数，若为0，则说明不需要补足；
按8个一组，依次读取字符串每一个字符，内部循环完成时，检查当前stringBuilder是否有8位，如果不足则补齐；
输出字符串并清空stringBuilder

import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Main {
    public static void main(String[] args) throws Exception {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String s = "";
        while ((s = br.readLine()) != null) {
            int patchLen = 8 - s.length() % 8;
            StringBuilder sb2 = new StringBuilder();
            for (int i = 0; i < s.length(); i = i + 8) {
                for (int j = i; j < i + 8 && j < s.length(); j++) {
                    sb2.append(s.charAt(j));
                }
                if (sb2.toString().length() != 8) {
                    for (int m = 0; m < patchLen; m++) {
                        sb2.append('0');
                    }
                }
                System.out.println(sb2.toString());
                sb2.setLength(0);
            }
        }
    }
}