select qd.difficult_level,sum(if(qpd.result='right',1,0))/count(qpd.question_id) as correct_rate from user_profile as up inner join question_practice_detail as qpd on up.device_id=qpd.device_id and university='浙江大学' inner join question_detail as qd on qpd.question_id=qd.question_id group by difficult_level order by correct_rate asc



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