# 每份试卷每月的作答数 和累计总作答数
select
exam_id,
date_format(start_time,'%Y%m') as start_month,
count(start_time) as month_cnt,
sum(count(start_time))over(partition by exam_id order by date_format(start_time,'%Y%m')) as cum_exam_cnt
from
exam_record
group by
exam_id,
start_month

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