题目描述:
给你一个链表,删除链表的倒数第 n 个结点,并且返回链表的头结点。
解析:
双指针:图片是删除倒数第二个节点
Java:
public ListNode removeNthFromEnd(ListNode head, int n) { ListNode dummy = new ListNode(0); dummy.next = head; ListNode n1 = dummy; ListNode n2 = dummy; for(int i = 0; i <= n; i++) { n2 = n2.next; } while(n2 != null) { n1 = n1.next; n2 = n2.next; } n1.next = n1.next.next; return dummy.next; }
JavaScript:
var removeNthFromEnd = function(head, n) { let dummy = new ListNode(); dummy.next = head; let n1 = dummy; let n2 = dummy; for(let i = 0; i <= n; i++) { n2 = n2.next; } while(n2 !== null) { n1 = n1.next; n2 = n2.next; } n1.next = n1.next.next; return dummy.next; };