题解 | 矩阵转置

n,m = map(int,input().split())
a = [list(map(int,input().split())) for _ in range(n)]
a_reverse = [[0]*n for _ in range(m)]
for i in range(n):
    for j in range(m):
        a_reverse[j][i] = a[i][j]
for i in range(m):
    s = ' '.join(list(map(str,a_reverse[i])))
    print(s)