题解 | #学英语#

num1 = ['zero','one','two','three','four','five','six',
       'seven','eight','nine','ten','eleven','twelve',
       'thirteen','fourteen','fifteen','sixteen',
       'seventeen','eighteen','nineteen']
num2 = [0,0,'twenty','thirty','forty','fifty','sixty',
       'seventy','eighty','ninety']
 
ListWords = []
def SumHundred(data):    #计算1-99
    if 0 < data <= 19:
        ListWords.append(num1[data])    # 0-19都是可以只用用num1数组进行转换
    elif 20 <= data <= 99:
        ListWords.append(num2[data//10])    # 在100以内，先判断十位取值
        if data % 10:    # 如果10位取值后，还有个位数不为0，需要继续取值到各位
            ListWords.append(num1[data % 10])    # 对10取余，则最大只有1-9

def SumThousand(data):    #计算100-999
    if 100 <= data  <= 999:
        ListWords.append(num1[data//100])    # 确认下有几百
        ListWords.append("hundred")
        if data % 100:        # 如果还有十位和个位，则调用函数处理
            ListWords.append("and")
    SumHundred(data%100)
            
while True:
    try:
        InputNum = int(input())
        BillionFlag = (InputNum // 1000000000) % 1000    # 统计1000000000-999999999999
        MillionFlag = (InputNum // 1000000) % 1000       # 统计1000000-999999999
        ThousandFlag = (InputNum // 1000) % 1000         # 统计1000-999999
        HundredFlag = InputNum % 1000                    # 统计1-999
        # 输入111,111,111,111
        # print(BillionFlag, MillionFlag, ThousandFlag, HundredFlag)
        if BillionFlag:    # 输出 one hundred and eleven billion
            SumThousand(BillionFlag)
            ListWords.append("billion")
        if MillionFlag:    # 输出 one hundred and eleven million
            SumThousand(MillionFlag)
            ListWords.append("million")
        if ThousandFlag:    # 输出 one hundred and eleven thousand
            SumThousand(ThousandFlag)
            ListWords.append("thousand")
        if HundredFlag:    # 输出 one hundred and eleven
            SumThousand(HundredFlag)
        # print(ListWords)
        print(" ".join(ListWords))
    except:
        break