题解 | #简单密码#

#include<iostream>
#include<string>
using namespace std;
int main()
{
    char a[] = {"22233344455566677778889999"};
    string in;
    cin >> in;
    for(int i = 0; i < in.size();i++)
    {
        if(in[i] >= 'a' && in[i] <= 'z')
            in[i] = a[in[i] - 'a'];
        else if((in[i] >= 'A' && in[i] < 'Z'))
            in[i] = in[i] + 'a'-'A' +1;
        else if(in[i] == 'Z')
            in[i] = 'a';
        else
            continue;
    }
    cout << in;
    return 0;
}
// 64 位输出请用 printf("%lld")