题解 | 特殊的科学计数法

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s;
    cin >> s;
    int a, b, c;
    c = s.size()-1;
    a = s[0]-'0';
    b=s[1]-'0';
    if(s[2]>'4'){
        if(s[1]!='9'){
            b=s[1]-'0'+1;
        }else if(a!=9) {
            b=0;
            a+=1;
        }else{
            a=1;
            b=0;
            c+=1;
        }
    }
    cout << a << "." << b << "*10^" << c << endl;

}
// 64 位输出请用 printf("%lld")