题解 | #字符串的反码#

#include <iostream>
#include <string>
using namespace std;

int main() {
    string str;
    cin>>str;
    for(int i = 0;i < str.size();i++){
        if(str[i] >= 'a' && str[i]<='z')
            str[i] = 'z'+'a'-str[i];//将字母翻转
        else if(str[i] >= 'A' && str[i]<='Z')
            str[i] = 'Z'+'A'-str[i];
        
    }
    cout<<str;
}
// 64 位输出请用 printf("%lld")