题意转化
我们把它想象成一张图,给你的是a>b,我们就从b向a连一条边,最后的时候每次以i结点遍历整张图。看看能遍历到几个点就行了,最后的时候答案要-1.因为第i个点也算了一遍。
code
#include <bits/stdc++.h>
#define N 100010
#define M 2010
using namespace std;
int n, m, head[M], add_edge, vis[M], ans;
struct node {
int next, to;
}edge[M];
int read() {
int s = 0, f = 0; char ch = getchar();
while (!isdigit(ch)) f |= (ch == '-'), ch = getchar();
while (isdigit(ch)) s = s * 10 + (ch ^ 48), ch = getchar();
return f ? -s : s;
}
void add(int from, int to) {
edge[++add_edge].next = head[from];
edge[add_edge].to = to;
head[from] = add_edge;
}
void dfs(int x) {
ans++; vis[x] = 1;
for (int i = head[x]; i; i = edge[i].next) {
int to = edge[i].to;
if (vis[to]) continue;
dfs(to);
}
}
int main() {
n = read(), m = read();
for (int i = 1, x, y; i <= m; i++) {
x = read(), y = read();
add(y, x);
}
for (int i = 1; i <= n; i++) {
memset(vis, 0, sizeof vis), ans = 0;
dfs(i);
cout << ans - 1<< "\n";
}
return 0;
}
``` 
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