主要是耐心,按照逻辑写好if-else if语句,奖励部分将范围小的判断放前面
import java.util.Scanner;
public class Main {
/**
*
* score 分数
* upCount 大写字母数目
* lowCount 小写字母数目
* numCount 数字数目
* sigCount 符号数目
*/
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while(in.hasNextLine()){
char[] ch = in.nextLine().toCharArray();
int score = 0;
//统计长度
int len = ch.length;
if(len <= 4) score += 5;
else if(len >4 && len < 8) score += 10;
else score += 25;
//遍历获取大小写字母、数字、符号数目
int upCount = 0;
int lowCount = 0;
int numCount = 0;
int sigCount = 0;
for (int i = 0; i < len; i++) {
if(Character.isUpperCase(ch[i])) ++upCount;
else if(Character.isLowerCase(ch[i])) ++lowCount;
else if(Character.isDigit(ch[i])) ++numCount;
else ++sigCount;
}
//字母分数
if((upCount > 0 && lowCount == 0) || (upCount == 0 && lowCount > 0)) score += 10;
else if(upCount > 0 && lowCount > 0) score += 20;
else score += 0;
//数字分数
if(numCount == 1) score += 10;
else if(numCount > 1) score += 20;
else score += 0;
//符号分数
if(sigCount == 1) score += 10;
else if(sigCount > 1) score += 25;
else score += 0;
//奖励分数
if (numCount > 0 && upCount > 0 && lowCount > 0 && sigCount > 0) score += 5;
else if(numCount > 0 && sigCount > 0 &&(upCount >0 || lowCount >0)) score += 3;
else if(numCount > 0 &&(upCount >0 || lowCount >0)) score += 2;
//评分
if(score >= 90) System.out.println("VERY_SECURE");
else if(score >= 80) System.out.println("SECURE");
else if(score >= 70) System.out.println("VERY_STRONG");
else if(score >= 60) System.out.println("STRONG");
else if(score >= 50) System.out.println("AVERAGE");
else if(score >= 25) System.out.println("WEAK");
else System.out.println("VERY_WEAK");
}
}
}