题解 | #小乐乐改数字#

#include <stdio.h>
int main() {
    int arr[10] = { 0 };
    int count = 0;
    int n = 0;
    int m = 0;
    int result = 0;
    scanf("%d", &n);
    while (n != 0) {
        m = n % 10;
        if (m % 2 == 0)
            arr[count++] = 0;
        else
            arr[count++] = 1;
        n = n / 10;
    }
    for (int i = count - 1; i >= 0; i--) {
        result = result * 10 + arr[i];
    }
    printf("%d", result);
    return 0;
}