select t2.difficult_level, round(sum(case when result = 'right' then 1 else 0 end )/count(*),4) correct_rate from question_practice_detail t1 left join question_detail t2 on t1.question_id = t2.question_id where t1.device_id in (select device_id from user_profile where university = '浙江大学') group by t2.difficult_level order by correct_rate