题解 | #在二叉树中找到两个节点的最近公共祖先#

class Solution:
    """二叉树的最近公共祖先 递归法"""

    def lowestCommonAncestor(self, root: 'TreeNode', p: 'TreeNode', q: 'TreeNode') -> 'TreeNode':
        if not root or root == p or root == q:
            return root
        
        left = self.lowestCommonAncestor(root.left, p, q)
        right = self.lowestCommonAncestor(root.right, p, q)
        
        if left and right:
            return root
        if left:
            return left
        return right