题解 | #奇偶统计#

#include <stdio.h>
int main() {
    int odd = 0;
    int i = 1;
    int sum1 = 0, sum2 = 0;
    int even = 0;
    int n = 0;
    while (scanf("%d", &n) != EOF) {
        for (i = 1; i <= n; i++) {
            if (i % 2 != 0) {
                sum1++;
            } else if (i % 2 == 0) {
                sum2++;
            }
        }
        printf("%d %d\n", sum1, sum2);
        sum1 = 0;
        sum2 = 0;
    }
    return 0;
}