题解 | #坐标移动#

#include<iostream>
#include<vector>
using namespace std;
int main()
{
    string str;
    cin >> str;
    int x = 0, y = 0, len = str.size(),fen=0;
    vector <string> vec;
    for(int i = 0; i < len; i++)
        if(str[i] == ';')
        {
            vec.push_back(str.substr(fen, i-fen));
            fen=i+1;
        }
    for(int i = 0; i < vec.size(); i++)
    {
        int num = 0;
        if(vec[i].size()==3&&vec[i][1]>='0'&&vec[i][1]<='9'&&vec[i][2]>='0'&&vec[i][2]<='9')
            num = (vec[i][1] - '0') * 10 + (vec[i][2] - '0');
        else if(vec[i].size()==2&&vec[i][1]<='9'&&vec[i][1]>='0')
            num = (vec[i][1] - '0');
        else continue;
        switch(vec[i][0])
        {
            case 'A': x -= num;break;
            case 'D': x += num;break;
            case 'S': y -= num;break;
            case 'W': y += num;break;
        }
    }
    cout << x << "," << y << endl;
}