题目链接:https://www.luogu.com.cn/problem/CF896C
题目大意:
这个数据读入有点毒瘤,其他解是模板了。
#include <bits/stdc++.h>
#define ll long long
#define sit set<node>::iterator
using namespace std;
struct node{
int l, r;
mutable ll val;
int operator<(const node &a) const{
return l<a.l;
}
node(int L, int R, ll Val): l(L), r(R), val(Val){}
node(int L) : l(L){}
};
struct odTree{
set<node> s;
sit Split(int pos){//一个节点分裂[l, r]->[l, pos-1]+[pos, r]
sit it=s.lower_bound(node(pos));
if(it!=s.end()&&it->l==pos) return it;
--it;
int l=it->l, r=it->r;
ll val=it->val;
s.erase(it);
s.insert(node(l, pos-1, val));
return s.insert(node(pos, r, val)).first;
}
void Assign(int l, int r, ll val){//区间赋值
sit it2=Split(r+1), it1=Split(l);
s.erase(it1, it2);
s.insert(node{l, r, val});
}
void Add(int l, int r, ll val){//区间[l, r]+=val
sit it2=Split(r+1), it1=Split(l);
for(sit it=it1; it!=it2; ++it) it->val+=val;
}
ll Kth(int l, int r, int k){//区间[l, r]的第k小
sit it2=Split(r+1), it1=Split(l);
vector<pair<ll, int> > aa;
aa.clear();
for(sit it=it1; it!=it2; ++it){
aa.push_back(pair<ll, int>(it->val, it->r-it->l+1) );
}
sort(aa.begin(), aa.end());
for(int i=0; i<aa.size(); ++i){
k-=aa[i].second;
if(k<=0) return aa[i].first;
}
}
ll qpow(ll a, int x, ll y){//求a^x%y
ll b=1ll;
a%=y;
while(x){
if(x&1) b=b*a%y;
a=a*a%y;
x>>=1;
}
return b;
}
ll Query(int l, int r, int x, ll y){//求[l, r], a[i]^x%y的和 暴力枚举+快速幂
sit it2=Split(r+1), it1=Split(l);
ll res=0;
for(sit it=it1; it!=it2; ++it){
res=(res+(it->r-it->l+1)*qpow(it->val, x, y)%y)%y;
}
return res;
}
}Tree;
int n, m, vmax;
ll seed;
int rd(){
int ret=(int)seed;
seed=(seed*7+13)%1000000007;
return ret;
}
int main(){
scanf("%d%d%lld%d", &n, &m, &seed, &vmax);
for(int i=1; i<=n; i++){
int a=rd()%vmax+1;
Tree.s.insert(node(i, i, (ll)a));
}
Tree.s.insert(node(n+1, n+1, 0));
for(int i=1; i<=m; i++){
int l, r, x, y;
int op=rd()%4+1;
l=rd()%n+1, r=rd()%n+1;
if(l>r) swap(l, r);
if (op == 3) x = rd() % (r - l + 1) + 1;
else x = rd() % vmax + 1;
if (op == 4) y = rd() % vmax + 1;
if (op == 1) Tree.Add(l, r, (ll)x);
else if (op == 2) Tree.Assign(l, r, (ll)x);
else if (op == 3) printf("%lld\n", Tree.Kth(l, r, x));
else if (op == 4) printf("%lld\n", Tree.Query(l, r, x, (ll)y));
}
return 0;
}
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