题解 | #表示数字#

s = input()  # Jkdi234klowe90a3   # Jkdi*234*klowe*90*a*3*
a = ""
pre_char = ""
for i in s:  # 此题是直接遍历字符串s
    if i.isdigit() and (not pre_char.isdigit()):
        a += "*"
    elif not i.isdigit() and (pre_char.isdigit()):
        a += "*"

    a += i
    pre_char = i
if i.isdigit():
    a += "*"
print(a)