三个空瓶可以换一瓶饮料 => 只能喝到1瓶
两个空瓶还可以借一瓶喝了换 => 刚刚好喝到一瓶
最优解就是每次都用两瓶去换...
最后额外附加的方法是模拟过程实现的;

import java.io.*;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String s = "";
        while ((s = br.readLine()) != null) {
            int bottle = Integer.parseInt(s);
            if (bottle == 0) {
                break;
            }
            System.out.println(bottle/2);
//             System.out.println(change(bottle));
        }
        br.close();
    }

    public static int change(int empty) {
        int drink = 0;
        while (empty > 3) {
            drink += empty / 3;
            empty = empty / 3 + empty % 3;
        }
        if (empty == 3 || empty == 2) {
            return drink + 1;
        } else {
            return drink;
        }
    }
}