题解 | #删除字符串中出现次数最少的字符#

import java.util.LinkedHashMap;
import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while(sc.hasNextLine()){
            char[] ch= sc.nextLine().toCharArray();
            Integer count = 0;
            LinkedHashMap<String,Integer> LHMap = new LinkedHashMap<String,Integer>();
            for (int i = 0; i < ch.length; i++) {
                if(LHMap.containsKey(String.valueOf(ch[i]))){
                    count = LHMap.get(String.valueOf(ch[i]))+1;
                    LHMap.put(String.valueOf(ch[i]),count);
                }else {
                    LHMap.put(String.valueOf(ch[i]),1);
                }
            }
            Integer minNum = LHMap.get(String.valueOf(ch[0]));
            for (String s : LHMap.keySet()) {
                //System.out.println(s+" "+LHMap.get(s));
                minNum = Math.min(minNum,LHMap.get(s));
            }
            /*System.out.println(String.valueOf(ch[3]));
            System.out.println("minNum="+minNum);
            System.out.println("LHMap.get(String.valueOf(ch[0])) = "+LHMap.get(String.valueOf(ch[0])));
            System.out.println("LHMap.get(ch[0]) = "+LHMap.get(ch[0]));*/
            /*
            assssa
            s
            minNum=2
            LHMap.get(String.valueOf(ch[0])) = 2
            LHMap.get(ch[0]) = null
            ssss
            * */
            
            StringBuilder str = new StringBuilder();
            for (int i = 0; i < ch.length; i++) {
                if(LHMap.get(String.valueOf(ch[i]))==minNum){
                    ch[i] = ' ';
                }
                if(ch[i]!=' '){
                    str.append(ch[i]);
                }
            }
            System.out.println(str);
        }
    }

}