题解 | #非整数倍数据位宽转换24to128#

`timescale 1ns/1ns

module width_24to128(
	input 				clk 		,   
	input 				rst_n		,
	input				valid_in	,
	input	[23:0]		data_in		,
 
 	output	reg			valid_out	,
	output  reg [127:0]	data_out
);

reg [3:0]   COUNT ;
reg [119:0] data_out_reg  ;


always@(posedge clk or negedge rst_n)begin
	if(!rst_n)
	    COUNT <= 'd0          ;
	else if(COUNT == 'd15 && valid_in == 1'b1)
	    COUNT <= 'd0          ;
	else if(valid_in == 1'b1)
	    COUNT <= COUNT + 1'b1 ;
end

//缓存120bit的数据 也就是五个 data_in
always@(posedge clk or negedge rst_n)begin
    if(!rst_n)
	    data_out_reg <= 'd0                          ;
    else if( valid_in == 1'b1)
	    data_out_reg <= {data_out_reg[95:0], data_in};
end


always@(posedge clk or negedge rst_n)begin
	if(!rst_n)
	    data_out <= 'd0                                     ;
	else if(COUNT == 'd5 && valid_in == 1'b1)                     // 24 24 24 24 24 8 
	    data_out <= {data_out_reg, data_in[23:16]}          ;
	else if(COUNT == 'd10 && valid_in == 1'b1)
	    data_out <= {data_out_reg[111:0],data_in[23:8]}     ; //{16 24 24 24},16
	else if(COUNT == 'd15 && valid_in == 1'b1)
	    data_out <= {data_out_reg[103:0],data_in}            ; //{8 24 24 24},24
	else 
	    data_out <= data_out                                 ;
end


always@(posedge clk or negedge rst_n)begin
    if(!rst_n)
	    valid_out <= 1'b0    ;
    else if((COUNT == 'd5 | COUNT == 'd10 | COUNT == 'd15) && valid_in == 1'b1)
	    valid_out <= 1'b1    ;
	else 
	    valid_out <= 1'b0    ;
end



endmodule

非整数倍数据位宽转换 需要找到转换的规律

24 24 24 24 24 {8，16} 24 24 24 24 {16， 8} 24 24 24 24 24