with tiaojian as ( select uid, count(id) as times from user_login_tb group by uid having count(id)>=3 ),tiaojian1 as ( select uid, count(distinct login_date) as days from user_login_tb group by uid having datediff((select max(login_date) from user_login_tb),max(login_date))>29 ) select t.uid, t1.days, t.times from tiaojian t inner join tiaojian1 t1 on t.uid=t1.uid order by days desc,times desc



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