题解 | #统计字符串中各类型字符的个数#

#include <iostream>
#include <cstring>
using namespace std;

int main() {

    int letter = 0;
    int digit = 0;
    int space = 0;
    int other = 0;
    
    char buf[1024] = {0};
    cin.getline(buf, sizeof(buf));

    // write your code here......
    for(int i = 0; i < strlen(buf); i++)
    {
        if((buf[i] >= 'a' && buf[i] <= 'z') || (buf[i] >= 'A' && buf[i] <= 'Z'))
            letter++;
        else if(buf[i] >= '0' && buf[i] <= '9')
            digit++;
        else if(buf[i] == ' ')
            space++;
        else 
            other++;

    }

    cout << "letter:" << letter << " digit:" << digit << " space:" << space << " other:" << other << endl;

    return 0;
}