中序遍历 然后输出数组的k小结点
class Solution: # 返回对应节点TreeNode def KthNode(self, pRoot, k): # write code here result=[] def inorder(head): if not head: return if head.left: inorder(head.left) result.append(head) if head.right: inorder(head.right) inorder(pRoot) if k>=1 and k<=len(result): return result[k-1] else: return None