中序遍历 然后输出数组的k小结点
class Solution:
# 返回对应节点TreeNode
def KthNode(self, pRoot, k):
# write code here
result=[]
def inorder(head):
if not head:
return
if head.left:
inorder(head.left)
result.append(head)
if head.right:
inorder(head.right)
inorder(pRoot)
if k>=1 and k<=len(result):
return result[k-1]
else:
return None
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