select sum(c.read_num) / sum(c.show_num) as fans_ctr from a join b on a.author_id = b.author_id join c on b.content_id = c.content_id where a.fans_id = c.fans_id
这题感觉怪怪的,不需要去重吗。回头要好好再理解一下
select sum(c.read_num) / sum(c.show_num) as fans_ctr from a join b on a.author_id = b.author_id join c on b.content_id = c.content_id where a.fans_id = c.fans_id
这题感觉怪怪的,不需要去重吗。回头要好好再理解一下