select
sum(c.read_num) / sum(c.show_num) as fans_ctr
from
a
join b on a.author_id = b.author_id
join c on b.content_id = c.content_id
where
a.fans_id = c.fans_id
这题感觉怪怪的,不需要去重吗。回头要好好再理解一下

select
sum(c.read_num) / sum(c.show_num) as fans_ctr
from
a
join b on a.author_id = b.author_id
join c on b.content_id = c.content_id
where
a.fans_id = c.fans_id
这题感觉怪怪的,不需要去重吗。回头要好好再理解一下