F题解 | Witcher Genshin Impact
既然大家都是线段树我就来个分块吧
#include <bits/stdc++.h>
using LL = long long;
using PII = std::pair<LL, LL>;
const int N = 1e5 + 10;
const int M = 330;
const int MOD = 1145141;
LL n, m, total, length, v[N], belong[N], sum[M], l[M], r[M], rnum[M];
void build() {
length = sqrt(n);
total = (n - 1)/length + 1;
for(int i = 1; i <= total; i++) {
l[i] = r[i - 1] + 1, r[i] = i*length;
}
r[total] = n;
for(int i = 1; i <= n; i++) belong[i] = (i - 1)/length + 1;
//处理每个块的和
for(int i = 1; i <= total; i++) {
LL all = 1;
for(int j = l[i]; j <= r[i]; j++) {
sum[i] = (sum[i] + v[j]*all)%MOD;
all = (all*v[j])%MOD;
if(j == r[i]) rnum[i] = all;
}
}
}
void modify(int pos, int val) {
v[pos] = val;
int now = belong[pos];
sum[now] = 0;
LL all = 1;
for(int i = l[now]; i <= r[now]; i++) {
sum[now] = (sum[now] + v[i]*all)%MOD;
all = (all*v[i])%MOD;
}
rnum[now] = all;
}
LL query(int L, int R) {
if(belong[L] == belong[R]) {
LL res = 0, all = 1;
for(int i = L; i <= R; i++) {
res = (res + all*v[i])%MOD;
all = (all*v[i])%MOD;
}
return res;
}
LL res = 0, tempr = 1;
for(int i = L; i <= r[belong[L]]; i++) {
res = (res + tempr*v[i])%MOD;
tempr = (tempr*v[i])%MOD;
}
for(int i = belong[L] + 1; i <= belong[R] - 1; i++) {
res = (res + tempr*sum[i])%MOD;
tempr = (tempr*rnum[i])%MOD;
}
for(int i = l[belong[R]]; i <= R; i++) {
res = (res + tempr*v[i])%MOD;
tempr = (tempr*v[i])%MOD;
}
return res;
}
void solve() {
std::cin >> n >> m;
for(int i = 1; i <= n; i++) std::cin >> v[i];
build();
while(m--) {
int op, a, b;
std::cin >> op >> a >> b;
if(op == 1) std::cout << query(a, b) << '\n';
else modify(a, b);
}
}
int main() {
std::ios::sync_with_stdio(0);
std::cin.tie(0);
std::cout.tie(0);
int T = 1;;
//std::cin >> T;
while (T--) solve();
return 0;
}