WITH
t1 AS (
SELECT
job,
DATE_FORMAT(date, '%Y-%m') AS first_year_mon,
SUM(num) AS first_year_cnt,
DATE_FORMAT(date, '%m') AS month1
FROM
resume_info
WHERE
YEAR(date) = 2025
GROUP BY
job,
DATE_FORMAT(date, '%Y-%m'), -- 确保所有非聚合列都在GROUP BY中
DATE_FORMAT(date, '%m') -- 添加month1对应的表达式
),
t2 AS (
SELECT
job,
DATE_FORMAT(date, '%Y-%m') AS second_year_mon,
SUM(num) AS second_year_cnt,
DATE_FORMAT(date, '%m') AS month2
FROM
resume_info
WHERE
YEAR(date) = 2026
GROUP BY
job,
DATE_FORMAT(date, '%Y-%m'), -- 确保所有非聚合列都在GROUP BY中
DATE_FORMAT(date, '%m') -- 添加month2对应的表达式
)
SELECT
t1.job,
t1.first_year_mon,
t1.first_year_cnt,
t2.second_year_mon,
t2.second_year_cnt
FROM
t1
LEFT JOIN t2
ON t1.job = t2.job
AND t1.month1 = t2.month2
order by first_year_mon desc, t1.job desc;