WITH t1 AS ( SELECT job, DATE_FORMAT(date, '%Y-%m') AS first_year_mon, SUM(num) AS first_year_cnt, DATE_FORMAT(date, '%m') AS month1 FROM resume_info WHERE YEAR(date) = 2025 GROUP BY job, DATE_FORMAT(date, '%Y-%m'), -- 确保所有非聚合列都在GROUP BY中 DATE_FORMAT(date, '%m') -- 添加month1对应的表达式 ), t2 AS ( SELECT job, DATE_FORMAT(date, '%Y-%m') AS second_year_mon, SUM(num) AS second_year_cnt, DATE_FORMAT(date, '%m') AS month2 FROM resume_info WHERE YEAR(date) = 2026 GROUP BY job, DATE_FORMAT(date, '%Y-%m'), -- 确保所有非聚合列都在GROUP BY中 DATE_FORMAT(date, '%m') -- 添加month2对应的表达式 ) SELECT t1.job, t1.first_year_mon, t1.first_year_cnt, t2.second_year_mon, t2.second_year_cnt FROM t1 LEFT JOIN t2 ON t1.job = t2.job AND t1.month1 = t2.month2 order by first_year_mon desc, t1.job desc;