题解 | #逆序输出#

#include<stdio.h>
int main()
{
    int* n=(int*)malloc(10*sizeof(int));
    int i,count1=0,count2=0;
    for(i=0;i<10;i++)
    {
        scanf("%d",&n[i]);
        if(n[i]>0)
            count1++;
        else if(n[i]<0)
            count2++;
    }
    printf("positive:%d\nnegative:%d\n",count1,count2);
    free(n);
    n=NULL;
    return 0;
}