题解 | 计算日期到天数转换

#include <iostream>
using namespace std;
int main() {
    int year, mon, day;
    int data[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    while (cin >> year >> mon >> day) {
        int sum;
        for (int i = 0; i < mon - 1; i++) {
            sum = sum + data[i];
        }
        if ((year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) && mon > 2)
            sum = sum + 1 + day;
        else
            sum = sum + day;
        cout << sum << endl;

    }
    return 0;
}