题解 | 单链表的排序

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 the head node
# @return ListNode类
#
class Solution:
    def sortInList(self , head: ListNode) -> ListNode:
        # write code here
        cur, arr = head, []
        while cur:
            arr.append(cur.val)
            cur = cur.next
        arr.sort()
        i, cur = 0, head
        while cur:
            cur.val = arr[i]
            i += 1
            cur = cur.next
        return head