题解 | #删除有序链表中重复的元素-I#

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @return ListNode类
 */
struct ListNode* deleteDuplicates(struct ListNode* head ) {
    if (head == NULL) {
        return 0;
    }
    struct ListNode*Next = head->next;
    struct ListNode*Pre = head;
    // write code here
    while (Next) {
        if (Pre->val == Next->val) {
            Pre->next = Next->next;
            Next = Next->next;
        }
        else {
            Pre = Pre->next;
            Next = Next->next;
        }
    }
    return head;
}