select d.difficult_level, avg(r1) correct_rate from ( select a.device_id, c.difficult_level, b.question_id, case when result = 'right' then 1 else 0 end r1 from user_profile a left join question_practice_detail b on a.device_id = b.device_id join question_detail c on b.question_id = c.question_id where a.university = '浙江大学' ) d group by d.difficult_level order by correct_rate;