select
d.difficult_level,
avg(r1) correct_rate
from
(
select
a.device_id,
c.difficult_level,
b.question_id,
case
when result = 'right' then 1
else 0
end r1
from
user_profile a
left join question_practice_detail b on a.device_id = b.device_id
join question_detail c on b.question_id = c.question_id
where
a.university = '浙江大学'
) d
group by
d.difficult_level
order by
correct_rate;

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