题解 | 简单密码

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string>

using namespace std;

//A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 密文
//V W X Y Z A B C D E F G H I J K L M N O P Q R S T U 明文

//复习ASCII码表
//数字和字母的起始值（0:48, A:65, a:97）。空格：32 逗号（,）的十进制值是 44

string s, e, str;

int main() {
    while (getline(cin, s)) {//若while (cin >> s)，会出现缓冲区残留换行符
        if (s == "ENDOFINPUT") {
            break;
        }
        else {
            getline(cin, str);
            cin >> e;
            for (int i = 0; i < str.size(); i++) {
                //只有ASCII码的值大于等于65时需要转换
                if (str[i] >= 65) {
                    if (str[i] == 'A') str[i] = 'V';
                    else if (str[i] == 'B') str[i] = 'W';
                    else if (str[i] == 'C') str[i] = 'X';
                    else if (str[i] == 'D') str[i] = 'Y';
                    else if (str[i] == 'E') str[i] = 'Z';
                    else str[i] -= 5;
                }
            }
        }
        cout << str << endl;
    }
    return 0;
}