http://tjuacm.chaosheng.top/problem.php?id=1289
https://vjudge.net/problem/POJ-1258
参考
https://blog.csdn.net/queen00000/article/details/81281823
最小生成树
这里用prim算法
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
using namespace std;
const int INF = 0x3f3f3f;
const int N = 110;
int n, sum;
int vis[N];
int dis[N];
int matrix[N][N];
void Prim(){ //从第一个点开始找周围最短的边
for(int i = 1; i <= n; i++){
dis[i] = matrix[1][i];
vis[i] = 0;
}
//printf("yes");
dis[1] = 0;
vis[1] = 1;
for(int i = 1; i < n; i++){ //寻找权值最小的点
int minn = INF, tmp;
for(int j = 1; j <= n; j++){
if(!vis[j] && dis[j] < minn){
minn = dis[j];
tmp = j;
}
}
sum += minn;
vis[tmp] = 1; //把点加入生成树;
for(int j = 1; j <= n; j++){ //利用新点改变其他不在最小生成树中的点的边
if(!vis[j] && dis[j] > matrix[tmp][j]){
dis[j] = matrix[tmp][j]; //更新
}
}
}
}
int main(){
while(cin >> n){
sum = 0;
for(int i = 1; i <= n; i++){
for(int j = 1; j <= n; j++){
cin >> matrix[i][j];
}
}
//printf("yes\n");
Prim();
printf("%d\n", sum);
}
return 0;
}
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