题解 | #牛牛的替换#

def f(s,a1,a2,a3,a4):
    if (a1 not in s) and (a3 not in s):
        return s

    if a1 in s:
       s = s.replace(a1,a2)

    if a3 in s:
       s = s.replace(a3,a4)
    
    return f(s,a1,a2,a3,a4)


dummy,a1,a2,a3,a4 = input().split()

s = input()

print(f(s,a1,a2,a3,a4))