题目链接：

https://www.nowcoder.com/practice/6d4a4cff1d58495182f536c548fee1ae?tpId=82&tqId=29759&tPage=1&rp=&ru=%2Fta%2Fsql&qru=%2Fta%2Fsql%2Fquestion-ranking

题目描述

查找薪水涨幅超过15次的员工号emp_no以及其对应的涨幅次数t
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

select emp_no,count(emp_no) AS t from salaries Group by emp_no HAVING t>15;

这个逻辑是不对的，暂时还不太清楚怎么搞哦