PAT基础编程题目-7-16 求符合给定条件的整数集
题目详情
解答
C语言版
#include<stdio.h>
int main()
{
int a;
scanf("%d", &a);
int number[4] = {
a, a+1, a+2, a+3};
int row = 0, col = 0; //统计行数和列数，控制行后面的换行和列后面的空格
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 4; j++) {
if (j!=i)
{
for (int k = 0; k < 4; k++)
{
if (k!=i && k!=j)
{
printf("%d%d%d", number[i], number[j], number[k]);
col++;
if (col<6)
printf(" ");
}
}
}
}
row++;
if (row<4)
printf("\n");
col = 0;
}
return 0;
}
C++
#include<iostream>
using namespace std;
int main() {
int a;
cin >> a;
int number[4] = {
a, a + 1, a + 2, a + 3 };
int row = 0, col = 0; //统计行数和列数，控制行后面的换行和列后面的空格
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 4; j++) {
if (j != i)
{
for (int k = 0; k < 4; k++)
{
if (k != i && k != j)
{
cout << number[i] << number[j] << number[k];
col++;
if (col < 6)
cout << " ";
}
}
}
}
row++;
if (row < 4)
cout << endl;
col = 0;
}
return 0;
}
Java版
import java.util.Scanner;
public class Main{
public static void main(String[] args) {
int a = 0;
Scanner scanner = new Scanner(System.in);
if (scanner.hasNext()) {
a = scanner.nextInt();
}
scanner.close();
int [] number = {
a, a + 1, a + 2, a + 3 };
int row = 0, col = 0; //统计行数和列数，控制行后面的换行和列后面的空格
for (int i = 0; i < 4; i++) {
for (int j = 0; j < 4; j++) {
if (j != i) {
for (int k = 0; k < 4; k++) {
if (k != i && k != j) {
/*System.out.print(number[i]); System.out.print(number[j]); System.out.print(number[k]);*/
// 采用一行输出则需要先转成字符串类型
System.out.print(Integer.toString(number[i])+Integer.toString(number[j])+Integer.toString(number[k]));
col++;
if (col < 6)
System.out.print(" ");
}
}
}
}
row++;
if (row < 4)
System.out.println();
col = 0;
}
}
}
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