题解 | 斗兽棋

//noob 54 斗兽棋
//二维数组
#include <stdio.h>

#include<string.h>

int main() {
    //1.定义棋子与编号的映射（0-3）
    char* pieces[4] = { "elephant", "tiger", "cat", "mouse" };
    //2.胜负表：win[a][b]
    int win[4][4] = {
        {0, 1, 0, 0},
        {0, .0, 1, 0},
        {0, 0, 0, 1},
        {1, 0, 0, 0}
    };
    char s1[20], s2[20];
    scanf("%s %s", s1, s2);

    //把输入字符串转为编号（a是s1的编号，b是s2的编号）
    //字符和数字编号的转换
    int a, b;
    for (a = 0; a < 4; a++) {
        if (strcmp(s1, pieces[a]) == 0)
            break;
    }
    for (b = 0; b < 4; b++) {
        if (strcmp(s2, pieces[b]) == 0)
            break;
    }
    if (a == b) {
        printf("tie\n");//相同棋子
    } else if (win[a][b])
        printf("win\n");//a赢b
    else if (win[b][a])
        printf("lose\n");//b赢a
    else
        printf("tie\n");


    return 0;
}