题解 | 简化目录路径

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param path string字符串 
# @return string字符串
#
class Solution:
    def simplifyPath(self , path: str) -> str:
        # write code here
        stack = []
        path = path.split("/")
        for ch in path:
            if ch == "." or ch == "":
                continue
            elif ch == "..":
                if stack:
                    stack.pop()
            else:
                stack.append(ch)
        return "/" + "/".join(stack)