//C++版代码 #include <iostream> #include <vector> #include <unordered_set> using namespace std; unordered_set<int> cols; unordered_set<int> diag1; unordered_set<int> diag2; vector<int> ans; void backtracking(int row, int result) { if (row == 8) { ans.push_back(result); return; } for (int i = 0; i < 8; i++) { if (cols.count(i) != 0) continue; if (diag1.count(row + i) != 0) continue; if (diag2.count(row - i) != 0) continue; cols.insert(i); diag1.insert(row + i); diag2.insert(row - i); backtracking(row + 1, result * 10 + i + 1); cols.erase(i); diag1.erase(row + i); diag2.erase(row - i); } } int main() { backtracking(0, 0); int b; while (cin >> b) { cout << ans[b - 1] << endl; } return 0; } //Java版代码 import java.util.*; public class Main { private static Set<Integer> columns = new HashSet<>(); private static Set<Integer> diagonals1 = new HashSet<>(); private static Set<Integer> diagonals2 = new HashSet<>(); private static List<Integer> ans = new ArrayList<>(); public static void main(String[] args) { Scanner sc = new Scanner(System.in); backtracking(0, 0); while (sc.hasNextInt()) { int b = sc.nextInt(); System.out.println(ans.get(b - 1)); } } private static void backtracking(int row, int result) { if (row == 8) { ans.add(result); return; } for (int i = 0; i < 8; i++) { if (columns.contains(i) || diagonals1.contains(row + i) || diagonals2.contains(row - i)) continue; columns.add(i); diagonals1.add(row + i); diagonals2.add(row - i); backtracking(row + 1, result * 10 + i + 1); columns.remove(i); diagonals1.remove(row + i); diagonals2.remove(row - i); } } } #Python版代码 def backtracking(row, result): if row == 8: ans.append(result) return for i in range(8): if i in columns or row - i in diagonals1 or row + i in diagonals2: continue columns.add(i) diagonals1.add(row - i) diagonals2.add(row + i) backtracking(row + 1, result * 10 + i + 1) columns.remove(i) diagonals1.remove(row - i) diagonals2.remove(row + i) ans = [] columns = set() diagonals1 = set() diagonals2 = set() backtracking(0, 0) while True: try: print(ans[int(input()) - 1]) except: break