select
t1.id as id,
t1.name as name,
t1.score as score
from
(
SELECT
g.id as id,
l.name AS name,
g.score as score,
DENSE_RANK() OVER (
PARTITION BY
g.language_id
ORDER BY
g.score DESC
# g.id asc
) AS ranking
FROM
grade g
LEFT JOIN language l ON g.language_id = l.id
) as t1
where
t1.ranking <= 2
order by name asc,ranking asc,id asc;



京公网安备 11010502036488号