题解 | #字符串分隔#

#include <iostream>
#include <string>
using namespace std;

int main() {
    string str;
    getline(cin, str);
    
    // 计算需要补充的0的个数
    int remainder = str.length() % 8;
    int padding = remainder == 0 ? 0 : 8 - remainder;
    
    // 补充0
    str.append(padding, '0');
    
    // 按8个字符分割并输出
    for(int i = 0; i < str.length(); i += 8) {
        cout << str.substr(i, 8) << endl;
    }
    
    return 0;
}

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        
        // 补充0直到长度是8的倍数
        StringBuilder sb = new StringBuilder(str);
        int remainder = sb.length() % 8;
        if (remainder != 0) {
            for (int i = 0; i < 8 - remainder; i++) {
                sb.append('0');
            }
        }
        
        // 每8个字符输出一行
        for (int i = 0; i < sb.length(); i += 8) {
            System.out.println(sb.substring(i, i + 8));
        }
    }
}

s = input()

# 补充0使长度为8的倍数
remainder = len(s) % 8
if remainder != 0:
    s += '0' * (8 - remainder)

# 每8个字符分割并输出
for i in range(0, len(s), 8):
    print(s[i:i+8])