三个题是100，44，85（小弟比较菜大佬勿喷）
第二题是真的没想明白
第三题我猜是无限循环问题我没解决(懒了感觉差不多就行了就没继续搞)

第一题：第一行输入一个数组，第二行输入两个整数i，len。从第i个整数开始输出len个数。如果数组超了，那就只输出到末尾。输出的时候，每二十个需要换行，每个输出用;隔开

第三题：输入多个结构体语句和一个sizeof语句，得到结构体大小。如果某个结构体出现未声明变量，则返回0。这题递归会溢出，需要优化

第二题：一共n个司机，输入四行，每行n个数。第一行输入距离，第二行输入阻塞距离，第三行输入红绿灯个数，第四行输入评分。普通距离速度10m/s，堵塞距离2m/s，红绿灯每个有50%概率等待15s。求得最短时间t的司机m。如果有司机评分高并且耗时t2<t+60，那么选评分高的司机。注意：普通距离要减去堵塞距离

代码不是最终结果，提交的有小改动

//3
import java.util.*;
class test{
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        HashMap<String, String> map = new HashMap<>();
        int flag = 0;
        String name = "";
        String member = "";
        String s = "";
        while(in.hasNext()){
            s = in.nextLine();

            if (flag == 0){
                name = s.substring(7, s.length() - 2);
                flag = 1;
            }else if (s.equals("}")){
                flag = 0;
                map.put(name, member);
                member = "";
            }else{
                member += s;
                member += "*";
            }
        }
        //System.out.println(s.substring(8, s.length() -1));
        System.out.println(size(s.substring(8, s.length() -1), map));
    }

    private static int size(String s, HashMap<String, String> map){
        String m = map.get(s);
        //System.out.println(m.substring(0, m.length() - 1));
        String[] arr = m.substring(0, m.length() - 1).split("\\*");

        int res = 0;
        for (int i = 0; i < arr.length; i++){
            String temp = arr[i];
            //System.out.println(temp.substring(4, 8));
            if (temp.substring(4, 8).equals("char")){
                res += 1;
            }else if (temp.substring(4, 8).equals("shor")){
                res += 2;
            }else if (temp.substring(4, 8).equals("long")){
                res += 4;
            }else {
                //System.out.println(temp.split(" ")[1]);
                //System.out.println(temp.substring(4));
                res += size(temp.substring(4).split(" ")[1], map);
            }
        }
        return res;
    }
}

----------------------------------------------------------------------------------------------------------------------
//1
import java.util.*;
class test{
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        while(in.hasNext()){
           String s = in.nextLine();
           int n = in.nextInt();
           int len = in.nextInt();
           helper(s, n, Math.min(n + len, s.length()));
        }
    }
    private static void helper(String s, int n, int len){
        int k = 0;
        String res = "";
        for (int i = n; i < len; i++){
            res += s.charAt(i);
            res += ";";
            k++;
            if (k == 20){
                System.out.println(res);
                res = "";
                k = 0;
            }
        }
        if (!res.equals("")){
            System.out.println(res);
        }
    }
}
-------------------------------------------------------------------------------------------------------------
//2 (第二题代码缺的比较多，主要是才44就不补出来了)
import java.util.*;
class test{
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        while(in.hasNext()){
            String s1 = in.nextLine();
            String s2 = in.nextLine();
            String s3 = in.nextLine();
            String s4 = in.nextLine();
            String[] arr1 = s1.split(" ");
            String[] arr2 = s2.split(" ");
            String[] arr3 = s3.split(" ");
            String[] arr4 = s4.split(" ");
            double[] time = new double[arr1.length];
            for (int i = 0; i < time.length; i++){
                time[i] = helper(Integer.valueOf(arr1[i]), Integer.valueOf(arr2[i]), Integer.valueOf(arr3[i]));
            }
            System.out.println(time[0]);
        }
    }

    private static double helper(int a, int b, int c){
        double time = (double)(a - b) / 10 + (double)b / 2 + (double)c * 15 / 2;
        return time;
    }
}