话说我不是首杀好难过
但是这样连边,复杂度是的
#include <bits/stdc++.h> using namespace std; #define ls (rt<<1) #define rs (rt<<1|1) #define mid (l+r>>1) #define lson ls,l,mid #define rson rs,mid+1,r const int maxn=6e6+10; const int inf=1e9; int n,m,s,t,dis[maxn],id; struct edge{ int to,nxt,flow; }d[maxn]; int head[maxn],cnt=1; int l[maxn],r[maxn],v[maxn]; void add(int u,int v,int flow){ d[++cnt]=(edge){v,head[u],flow},head[u]=cnt; d[++cnt]=(edge){u,head[v],0},head[v]=cnt; } bool bfs() { for(int i=s;i<=t;i++) dis[i]=0; dis[s]=1; queue<int>q; q.push( s ); while( !q.empty() ) { int u=q.front(); q.pop(); for(int i=head[u];i;i=d[i].nxt ) { int v=d[i].to; if( d[i].flow&&dis[v]==0 ) { dis[v]=dis[u]+1; if( v==t ) return true; q.push( v ); } } } return false; } int dinic(int u,int flow) { if( u==t ) return flow; int res=flow; for(int i=head[u];i&&res;i=d[i].nxt ) { int v=d[i].to; if( dis[v]==dis[u]+1&&d[i].flow) { int temp=dinic(v,min(res,d[i].flow) ); if( temp==0 ) dis[v]=0; res-=temp; d[i].flow-=temp; d[i^1].flow+=temp; } } return flow-res; } void build(int rt,int l,int r) { id = max( id,n+m+rt ); if( l==r ){ add(rt+m+n,l+m,inf); return; } build(lson); build(rson); add(rt+m+n,ls+m+n,inf); add(rt+m+n,rs+m+n,inf); } void run(int rt,int l,int r,int u,int L,int R) { if( r<L||l>R ) return; if( L<=l&&R>=r ) { add(u,rt+n+m,inf); return; } run(lson,u,L,R); run(rson,u,L,R); } signed main() { while( cin >> n >> m ) { s=0,id=0; build(1,1,n); for(int i=1;i<=m;i++) { scanf("%d%d%d",&l[i],&r[i],&v[i] ); run(1,1,n,i,l[i],r[i] ); add(s,i,v[i] ); } t = id+1; for(int i=1;i<=n;i++) add(i+m,t,1); int ans=0; while( bfs()) ans+=dinic(s,inf); cout << ans << '\n'; cnt = 1; for(int i=s;i<=t;i++) head[i]=0; } }