题解 | #打印每一行出现的数字个数#

#/bin/bash
linecount=0
sum=0
count=0

while read line
do
    for (( i=0; i<${#line};i++ ))
    do
        if [[  ${line:$i:1} =~ [1-5] ]]
        then
            count=$(($count+1))
        fi
    done
    linecount=$(($linecount+1))
    echo "line$linecount number:$count"
    sum=$(($sum+$count))
    count=0

done<nowcoder.txt
echo "sum is $sum"
#####################################
coutline=0
count=0
sum=0
while read line
do
    for((i=0;i<${#line};i++));do
        if [[ ${line:$i:1} =~ [1-5] ]];then
            let count=count+1
        fi
    done
    let coutline=coutline+1
    echo "line${coutline} number: ${count}"
    let sum=sum+count
    count=0
done<./nowcoder.txt
echo "sum is ${sum}"
#####################################
#!/bin/bash
declare -A m

line=1
while read l
do
  len=${#l}
  for((i=0;i<$len;i++))
  do
    if [[ ${l:$i:1} =~ [1-5] ]];then
      ((m[$line]++))
    fi
  done

  if [[ -z ${m[$line]} ]];then
    m[$line]=0
  fi

  ((line++))
done < nowcoder.txt

sum=0
for i in ${!m[@]}
do
  echo "line${i} number: ${m[$i]}"
  sum=$[$sum+${m[$i]}]
done

echo "sum is $sum"
#####################################
awk '{
    gsub(/[^1-5]/,"",$0);
    print "line"NR" number: "length($0);
    sum+=length($0);
} END{print "sum is "sum}'
#####################################

awk '{
    gsub(/[^1-5]/,"",$0);
    print "line"NR" number: "length($0);
    sum+=length($0);
} END{ print "sum is "sum }' nowcoder.txt