题解 | #特殊乘法#

#include <iostream>
using namespace std;

int main() {
    string a;
    string b;
    int x = 0;
    cin >> a >> b;
    for (int i = 0; i < a.size(); ++i) {
        for (int j = 0; j < b.size(); ++j) {
            x += (a[i] - 48) * (b[j] - 48);//ASCII对应数字
        }
    }
    std::cout << x << std::endl;
}