太慢了，用的stl优先队列，以后用堆做一做

#include<cstdio>
#include<queue>
using namespace std;
//用两个优先队列，保存下最大和最小的几个数
int main()
{
    double sum = 0;
    int n1,n2,n,t;
    priority_queue<int> small;
    priority_queue<int,vector<int>,greater<int> > big;
    while(scanf("%d%d%d",&n1,&n2,&n),n1)
    {
        sum = 0;
        for(int i = 1;i<=n;++i)
        {
            scanf("%d",&t);
            sum += t;
            small.push(t);
            big.push(t);
            if(small.size()>n2) small.pop();
            if(big.size()>n1) big.pop();
        }
        while(!small.empty())
        {
            sum -= small.top();
            small.pop();
        }
        while(!big.empty())
        {
            sum -= big.top();
            big.pop();
        }
        printf("%.6f\n",sum/(1.0*(n-n1-n2)));
    }
    return 0;
}