题解 | 牛牛的字符矩形

#include <stdio.h>
int main() {
    char a[3][3], n;
    int i = 0, j = 0;
    scanf("%c", &n);
    for (i = 0; i < 3; i++) {
        for (j = 0; j < 3; j++) {
            a[i][j] = n;
            printf("%c", a[i][j]);
        }
        printf("\n");
    }
    return 0;
}