题解 | #百钱买百鸡问题#

#include <iostream>
using namespace std;

int main(){
    int n;
    int num = 100;
    int jw = 0;
    int jm = 0;
    int jc = 0;
    while(cin >> n){
        for(int i = 0; i < num/5; i++){    
            for(int j = 0; j < num/3; j++){             
                for(int k = 0; k < 3*num; k++){
                    if((i * 5 + j * 3 + k / 3.0) == 100 && (i+j+k) == 100){ //k/3.0保证K能被整除，没有余数
                        cout << i << " "<< j << " "<< k <<endl;
                    }
                }
            }
        } 
    } 
    return 0;
}